(25k^-2)^2/5k^-9

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Solution for (25k^-2)^2/5k^-9 equation: 


D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

k^-9*(((25*k^-2)^2)/5) = 0

125*k^-13 = 0 // : 125

k^-13 = 0

k należy do O

k belongs to the empty set

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